Section 1.4 displacement field
Another quantity widely used in the kinematic description of bodies is the difference between the current position and the reference position of the generic point
known as displacement field. The relative gradient, known as displacement gradient and indicated with the symbol \(\tens{\nabla u}\text{,}\) is obtained in a similar way to what has already been done for the deformation gradient. Given the field
the following result can be obtained
From Equation (1.4.1) the relationship between displacement gradient and deformation can be easily obtained
where \(\tens{I}\text{,}\) the identity tensor, is
evaluation of the displacement field and its gradient.
With regard to the Transformation 1 already used in the previous examples, the displacement field and its gradient can be evaluated on the basis of the following MATLAB® instructions. Bear in mind that, for the linearity of the transformations involved, the gradients are evaluated as the matrix associated to the transformation. T1 = @(X) [-X(2); X(1)];
F = [T1([1; 0]) T1([0; 1])]
Grad_u = F - diag([1 1])
u1 = @(X) T1(X) - X;
Grad_u = [u1([1; 0]) u1([0; 1])]
MATLAB® instructions for Transformation 2. T2 = @(X) [2*X(1); X(2)];
F = [T2([1; 0]) T2([0; 1])]
Grad_u = F - diag([1 1])
u2 = @(X) T2(X) - X;
Grad_u = [u2([1; 0]) u2([0; 1])]
MATLAB® instructions for Transformation 3. T3 = @(X) [X(1); 1.5*X(2)];
F = [T3([1; 0]) T3([0; 1])]
Grad_u = F - diag([1 1])
u3 = @(X) T3(X) - X;
Grad_u = [u3([1; 0]) u3([0; 1])]
MATLAB® instructions for Transformation 4. T4 = @(X) [X(1)+X(2); X(2)];
F = [T4([1; 0]) T4([0; 1])]
Grad_u = F - diag([1 1])
u4 = @(X) T4(X) - X;
Grad_u = [u4([1; 0]) u4([0; 1])]